Offer_day07_26. 树的子结构
代码:
import time
from typing import List
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution:
def __init__(self):
pass
def isSame(self, A: TreeNode, B: TreeNode) -> bool:
if A is not None and B is not None:
if B.val==A.val:
return self.isSame(A.left,B.left) and self.isSame(A.right,B.right)
else:
return False
elif B is None:
return True
else:
return False
def isSubStructure(self, A: TreeNode, B: TreeNode) -> bool:
if B is None:return False
queue = [A]
while len(queue):
head = queue.pop(0)
if head:
if self.isSame(head,B):return True
queue.append(head.left)
queue.append(head.right)
return False
class Solution_官方:
def isSubStructure(self, A: TreeNode, B: TreeNode) -> bool:
def recur(A, B):
if not B: return True
if not A or A.val != B.val: return False
return recur(A.left, B.left) and recur(A.right, B.right)
return bool(A and B) and (recur(A, B) or self.isSubStructure(A.left, B) or self.isSubStructure(A.right, B))
def test(data_test):
s = Solution()
return s.isSubStructure(*data_test)
def test_obj(data_test):
result = [None]
obj = Solution(*data_test[1][0])
for fun, data in zip(data_test[0][1::], data_test[1][1::]):
if data:
res = obj.__getattribute__(fun)(*data)
else:
res = obj.__getattribute__(fun)()
result.append(res)
return result
if __name__ == '__main__':
datas = [
[],
]
for data_test in datas:
t0 = time.time()
print('-' * 50)
print('input:', data_test)
print('output:', test(data_test))
print(f'use time:{time.time() - t0}s')
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备注:
GitHub:https://github.com/monijuan/leetcode_python
CSDN汇总:模拟卷Leetcode 题解汇总_卷子的博客-CSDN博客
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leetcode_python.utils详见汇总页说明
先刷的题,之后用脚本生成的blog,如果有错请留言,我看到了会修改的!谢谢!
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