点击链接PAT甲级-AC全解汇总

题目：
Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:
Each input file contains one test case. For each case, the first line contains two integers N (≤10^​5​​ ) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student’s record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID’s; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID’s in increasing order.

Sample Input 1:

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60
1
2
3
4

Sample Output 1:

000001 Zoe 60
000007 James 85
000010 Amy 90
1
2
3

Sample Input 2:

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98
1
2
3
4
5

Sample Output 2:

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60
1
2
3
4

Sample Input 3:

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90
1
2
3
4
5

Sample Output 3:

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90
1
2
3
4

题意：
题目不难，就是N个学生，三种排序方式输出

注意： 如果用for(int i=0;i

我的代码：

#include
using namespace std;

class Stu
{
public:
    Stu(int id,string name,int score):id_(id),name_(name),score_(score){}
    int id_,score_;
    string name_;
};

bool cmp1(Stu a,Stu b){
    return a.id_<b.id_;
}
bool cmp2(Stu a,Stu b){
    if(a.name_!=b.name_)return a.name_<b.name_;
    else return a.id_<b.id_;
}
bool cmp3(Stu a,Stu b){
    if(a.score_!=b.score_)return a.score_<b.score_;
    else return a.id_<b.id_;
}

int main()
{
    int N,c;
    cin>>N>>c;

    vector<Stu>all;
    for(int i=0;i<N;i++)
    {
        int id,sc;
        string name;
        cin>>id>>name>>sc;
        Stu t(id,name,sc);
        all.push_back(t);
    }
    if(c==1)sort(all.begin(),all.end(),cmp1);
    else if(c==2)sort(all.begin(),all.end(),cmp2);
    else sort(all.begin(),all.end(),cmp3);

    for(auto it:all)
    {
        printf("%06d ",it.id_);
        cout<<it.name_<<" "<<it.score_<<endl;
    }
    return 0;
}

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