点击链接PAT甲级-AC全解汇总

题目：
Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.

Input Specification:
Each input file contains one test case. For each case, the first line contains a positive number N (≤100), the number of test locations. Then N ranklists follow, each starts with a line containing a positive integer K (≤300), the number of testees, and then K lines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.

Output Specification:
For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:

registration_number final_rank location_number local_rank
1

The locations are numbered from 1 to N. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.

Sample Input:

2
5
1234567890001 95
1234567890005 100
1234567890003 95
1234567890002 77
1234567890004 85
4
1234567890013 65
1234567890011 25
1234567890014 100
1234567890012 85
1
2
3
4
5
6
7
8
9
10
11
12

Sample Output:

9
1234567890005 1 1 1
1234567890014 1 2 1
1234567890001 3 1 2
1234567890003 3 1 2
1234567890004 5 1 4
1234567890012 5 2 2
1234567890002 7 1 5
1234567890013 8 2 3
1234567890011 9 2 4
1
2
3
4
5
6
7
8
9
10

题意：
学生成绩分考场输入，输出总排名和考场号和考场排名。
不是很难的样子，不重写了。
（总看不惯算法笔记很正式的代码，我还是觉得做题目只要解决问题就好了，对症下药即可，没必要扩展性很好。也可能是我太菜才这么觉得吧）

算法笔记的代码：

#include
#include
#include
using namespace std;
struct Student{
    char id[15];
    int score;
    int location_number;
    int local_rank;
}stu[100000];
bool cmp(Student a,Student b){
    if(a.score!=b.score)
        return a.score>b.score;
    else
        return strcmp(a.id,b.id)<0;
}

int main(){
    int n,k,num=0;
    scanf("%d",&n);
    for(int i=1;i<=n;i++){
        scanf("%d",&k);
        for(int j=0;j<k;j++){
           scanf("%s %d",stu[num].id,&stu[num].score);
           stu[num].location_number=i;
           num++;
        }
        sort(stu+num-k,stu+num,cmp);
        stu[num-k].local_rank=1;
        for(int j=num-k+1;j<num;j++){
            if(stu[j].score==stu[j-1].score)
                stu[j].local_rank=stu[j-1].local_rank;
            else
                stu[j].local_rank=j+1-(num-k);
        }
    }
    printf("%d\n",num);
    sort(stu,stu+num,cmp);
    int r=1;
    for(int i=0;i<num;i++){
        if(i>0&&stu[i].score!=stu[i-1].score)
            r=i+1;
        printf("%s ",stu[i].id);
        printf("%d %d %d\n",r,stu[i].location_number,stu[i].local_rank);
    }
    return 0;
}
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